Question
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Evaluate the expression without using a calculator. \( \operatorname{arccsc}(2) \)

Ask by Davison Powell. in the United States
Feb 26,2025

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Tutor-Verified Answer

Answer

arccsc(2) is equal to π/6.

Solution

To evaluate arccsc(2), we start by recalling the definition of the inverse cosecant function. 1. The function arccsc(2) is defined as the angle θ for which   csc θ = 2. 2. Since csc θ is the reciprocal of sin θ, we have:   csc θ = 2 ⟹ 1/sin θ = 2 ⟹ sin θ = 1/2. 3. Now, we look for the angle θ such that sin θ = 1/2. Within the principal range of the inverse sine function (typically -π/2 ≤ θ ≤ π/2, excluding 0 for the cosecant inverse when necessary), the angle satisfying sin θ = 1/2 is:   θ = π/6. Thus, the value of arccsc(2) is π/6.

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Beyond the Answer

To evaluate \( \operatorname{arccsc}(2) \), we start by recalling that the cosecant function is the reciprocal of sine. Therefore, \( \operatorname{arccsc}(2) \) is asking for the angle whose cosecant is 2. This means we need to find an angle \( \theta \) such that: \[ \csc(\theta) = 2 \] Since cosecant is the reciprocal of sine, we can rewrite this as: \[ \sin(\theta) = \frac{1}{2} \] The basic sine value of \( \frac{1}{2} \) occurs at angles in the unit circle. We know that: \[ \sin\left(\frac{\pi}{6}\right) = \frac{1}{2} \] Thus, the principal value (the angle in the range of \( \left(-\frac{\pi}{2}, \frac{\pi}{2}\right) \)) that corresponds to \( \sin(\theta) = \frac{1}{2} \) is: \[ \theta = \frac{\pi}{6} \] Hence, we have: \[ \operatorname{arccsc}(2) = \frac{\pi}{6} \]

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