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Solve for \( x \) using the square root property. \( x^{2}-29=0 \) \( x=1 \)

Ask by Deleon Frazier. in the United States
Mar 09,2025

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Tutor-Verified Answer

Answer

The solutions are \( x = \sqrt{29} \) and \( x = -\sqrt{29} \).

Solution

We start with the equation \[ x^{2} - 29 = 0. \] **Step 1: Isolate the squared term.** Add \(29\) to both sides: \[ x^{2} = 29. \] **Step 2: Apply the square root property.** Taking the square root of both sides, remember to include both positive and negative solutions: \[ x = \pm \sqrt{29}. \] Thus, the solutions are \[ x = \sqrt{29} \quad \text{or} \quad x = -\sqrt{29}. \]

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Beyond the Answer

To solve the equation \( x^{2} - 29 = 0 \), we first isolate \( x^{2} \) by adding 29 to both sides, giving us \( x^{2} = 29 \). Next, we apply the square root property, which tells us that \( x \) can be either the positive or negative square root of 29. Thus, we have \( x = \sqrt{29} \) or \( x = -\sqrt{29} \). Therefore, the solutions are \( x \approx 5.39 \) and \( x \approx -5.39 \). Now, it's important to double-check mistakes. If you initially thought that \( x = 1 \) was a solution, remember that squaring 1 yields 1, which won’t satisfy the original equation since \( 1 - 29 = -28 \) is not equal to 0. Always check your work to avoid such slip-ups!

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