6. The diameter of a circular microorganism is 8.8 nanometres. Find the (i) circumference in m , (ii) area in \( \mathrm{m}^{2} \), of the microorganism. Give your answers in standard form. (Take \( \pi=3.142,1 \) nanometre \( =10^{-9} \) metres.)

To find the circumference and area of the circular microorganism with a diameter of 8.8 nanometres, we can follow these steps: First, convert the diameter to metres: \[ \text{Diameter} = 8.8 \text{ nm} = 8.8 \times 10^{-9} \text{ m} \] Now, we can find the circumference (C) using the formula: \[ C = \pi \times \text{Diameter} \] Substituting in our values: \[ C = 3.142 \times (8.8 \times 10^{-9}) \approx 2.77 \times 10^{-8} \text{ m} \] Next, we find the area (A) using the formula: \[ A = \pi \times \left(\frac{\text{Diameter}}{2}\right)^2 \] First, calculate the radius: \[ \text{Radius} = \frac{8.8 \times 10^{-9}}{2} = 4.4 \times 10^{-9} \text{ m} \] Now substitute: \[ A = 3.142 \times (4.4 \times 10^{-9})^2 \approx 6.09 \times 10^{-17} \text{ m}^{2} \] Thus, the answers in standard form are: (i) Circumference \( \approx 2.77 \times 10^{-8} \text{ m} \) (ii) Area \( \approx 6.09 \times 10^{-17} \text{ m}^{2} \)