If $$ \log _{2}(3 x+4)=5 $$, then $$ x=\square $$ You may enter the exact value or round to 4 decimal places. Submit and End

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Solve the equation $$ \log_{2}(3x+4)=5 $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$\log_{2}{\left(3x+4\right)}=5$$
- step1: Find the domain:
  $$\log_{2}{\left(3x+4\right)}=5,x>-\frac{4}{3}$$
- step2: Convert the logarithm into exponential form:
  $$3x+4=2^{5}$$
- step3: Evaluate the power:
  $$3x+4=32$$
- step4: Move the constant to the right side:
  $$3x=32-4$$
- step5: Subtract the numbers:
  $$3x=28$$
- step6: Divide both sides:
  $$\frac{3x}{3}=\frac{28}{3}$$
- step7: Divide the numbers:
  $$x=\frac{28}{3}$$
- step8: Check if the solution is in the defined range:
  $$x=\frac{28}{3},x>-\frac{4}{3}$$
- step9: Find the intersection:
  $$x=\frac{28}{3}$$
The solution to the equation $$ \log_{2}(3x+4)=5 $$ is $$ x = \frac{28}{3} $$ or $$ x \approx 9.333 $$ when rounded to 4 decimal places.
$$ x = \frac{28}{3} $$ or $$ x \approx 9.3333 $$

If \( \log _{2}(3 x+4)=5 \), then \( x=\square \) You may enter the exact value or round to 4 decimal places. Submit and End

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