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Hallar: \( x^{2}+1 \) si: \( 5^{x+1}+5^{x}=150 \)

Ask by Rowe Cook. in Peru
Feb 17,2025

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La respuesta es 5.

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Dada la ecuación:   5^(x+1) + 5^x = 150 Paso 1: Escribir 5^(x+1) como 5 · 5^x   Entonces la ecuación se convierte en:   5 · 5^x + 5^x = 150 Paso 2: Factorizar 5^x en el lado izquierdo:   5^x (5 + 1) = 150   6 · 5^x = 150 Paso 3: Despejar 5^x   5^x = 150 / 6 = 25 Paso 4: Reconocer que 25 = 5^2, por lo tanto:   5^x = 5^2   De aquí se deduce que:   x = 2 Paso 5: Calcular x² + 1   x² + 1 = 2² + 1 = 4 + 1 = 5 La respuesta final es: 5.

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Para resolver la ecuación \( 5^{x+1} + 5^{x} = 150 \), primero podemos notar que \( 5^{x+1} = 5 \cdot 5^{x} \). Sustituyendo esto en la ecuación, obtenemos: \[ 5 \cdot 5^{x} + 5^{x} = 150. \] Esto se simplifica a: \[ 6 \cdot 5^{x} = 150. \] Dividiendo ambos lados entre 6, tenemos: \[ 5^{x} = 25. \] Como \( 25 = 5^{2} \), podemos igualar las bases y resolver: \[ x = 2. \] Ahora, para hallar \( x^{2} + 1 \): \[ x^{2} + 1 = 2^{2} + 1 = 4 + 1 = 5. \] Así que la respuesta es \( x^{2}+1 = 5 \).

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