Solve for $$ x $$ $$ 0.8^{(2 x+1)}=1 $$

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Solve the equation $$ 0.8^{(2x+1)}=1 $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$0.8^{\left(2x+1\right)}=1$$
- step1: Simplify:
  $$\left(\frac{4}{5}\right)^{2x+1}=1$$
- step2: Write in exponential form:
  $$\left(\frac{4}{5}\right)^{2x+1}=\left(\frac{4}{5}\right)^{0}$$
- step3: Set the exponents equal:
  $$2x+1=0$$
- step4: Move the constant to the right side:
  $$2x=0-1$$
- step5: Remove 0:
  $$2x=-1$$
- step6: Divide both sides:
  $$\frac{2x}{2}=\frac{-1}{2}$$
- step7: Divide the numbers:
  $$x=-\frac{1}{2}$$
The solution to the equation $$0.8^{(2x+1)}=1$$ is $$x=-\frac{1}{2}$$ or $$x=-0.5$$.
$$ x = -0.5 $$

Solve for \( x \) \( 0.8^{(2 x+1)}=1 \)

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