Solve for \( x \) \( 0.8^{(2 x+1)}=1 \)

To solve the equation \( 0.8^{(2 x+1)}=1 \), we first recognize that any number raised to the power of 0 equals 1. Thus, we can rewrite our equation as: \[ 2x + 1 = 0 \] Next, we can solve for \( x \): 1. Subtract 1 from both sides: \[ 2x = -1 \] 2. Divide by 2: \[ x = -\frac{1}{2} \] So the solution for \( x \) is: \[ \boxed{-\frac{1}{2}} \]