Moreno Gordon
06/10/2024 · High School
You found some, but not all, of the correct numbers. Use the quadratic formula to solve for \( x \). \[ 4 x^{2}+6 x-1=0 \] (If there is more than one solution, separate them with commas.)
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\(x_{1}=-\frac{3+\sqrt{13}}{4}, x_{2}=\frac{-3+\sqrt{13}}{4}\)
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