girl-logo

Ask Questions

Physics Questions & Answers

Q:
1.4 The pump delivers water at a pressure of \( 16 k P a \) while it does \( 24 k J \) work per minute. Calculate: 1.4.1 The volume of water delivered in liters per second 1.4.2 The input power to the pump if it has an efficiency of \( 80 \% \)
Q:
A horizontal force of magnitude 80 kg .wt is applied to a container of weight 80 kg ,wt containing 24 boxes, each box of weight \( 20 \mathrm{~kg}, \mathrm{wt} \) on a rough horizontal ground. The coefficient of static friction between it and the container is \( \frac{1}{6} \), find the number of boxes that must be removed so that the container is about to move on the ground.
Q:
A horizontal force of magnitude \( 80 \mathrm{~kg} . \mathrm{wt} \) is applied to a container of weight 80 kg ,wt containing 24 boxes, each box of weight 20 kg ,wt on a rough horizontal ground. The coefficient of static friction between it and the container is \( \frac{1}{6} \), find the number of boxes that must be removed so that the container is about to move on the ground
Q:
Calcular el trabajo para elevar hasta 12 metros en cuerpo de 15 kgf 2) Se eleva un cuerpo hasta 3 m mediante un trabajo de 75 kgm ¿Cuál es el peso del cuerpo? 3) Para subir un tonel hasta 3 m de altura ha sido neceṣario un trabajo de 240 kgm ¿Cuánto pesa el tonel? 4) ¿Qué trabajo (en Julio y kilovatios-hora) realizará un hombre para elevar una bolsa de 70 kgf a una altura de \( 2,5 \mathrm{~m} \) ? 5) ¿Qué energía cinética alcanzará un cuerpo que pesa 38 kgf a los 30 segundos de caída libre?
Q:
मयाधान: \( \mathrm{E}=\frac{\mathrm{hc}}{\lambda}=\frac{6.63 \times 10^{-34} \times 3 \times 10^{6}}{3000 \times 10^{-10}} \mathrm{~J}=6.63 \times 10^{-19} \mathrm{~J}=4.14 \mathrm{eV} \) \[ \mathrm{E}_{\mathrm{k}}=\mathrm{E}-\phi=(4.14-2.3) \mathrm{eV}=1.84 \mathrm{eV} \] 02. UV radiation having a 300 mm wavelength falls on uranium metal, ejecting 0.5 cV electrons. What is the binding energy of electrons to uranium metal? (Planck's constant \( =6.63 \times 10^{-34} \mathrm{kgm}^{2} \mathrm{~s}^{-1} \) )
Q:
A body of weight \( 30 \mathrm{~kg} . \mathrm{wt} \) is placed on a rough horizontal plane. A horizontal force of magnitude Fkg .wt is applied to it, making it about to move. If the measure of the angle between the resultant reaction and the limiting friction force is \( \theta \), where \( \cos \theta=\frac{5}{13} \). find the value of the resultant reaction.
Q:
A cold piece of metal is placed into a cup of hot water. This causes the temperature of the water to fall \( 5.25^{\circ} \mathrm{C} \). The original temperature of the water was \( 62.4^{\circ} \mathrm{C} \). What is the new temperature?
Q:
6. Como a gravidade e a força centrípeta influenciam atividades do dia a dia, como andar de bicicleta em uma curva? - Relacione como a força centrípeta mantém o ciclista na trajetória curva e como a velocidade afeta essa força.
Q:
14. Seorang ilmuwan melakukan percobaan menembakkan proyektil. Proyektil ditembakkan ke udara dengan sudut tertentuterhadap horizontal, dan selama bergerak, proyektil mengikuti lintasan parabola. Ketinggian proyektil dalam \( h \) meter terhadap waktu \( t \) dalam detik setelah ditembakkan dapat dinyatakan dengan persamaan \( h(t)=-4 \mathrm{t}^{2}+16 \mathrm{t}+50 \). Jika kelajuan proyekti sepanjang sumbu horizontal sebesar \( 10 \mathrm{~m} / \mathrm{s} \), maka jarak horizontal proyektil saat ia mencapai titik maksimum diukur dari titik awal ia ditembakkan adalah .... a. 10 m b. 20 m c. 30 m d. 40 m e. 50 m
Q:
15. In an archery competition, an archer stands on a hill so that the arrow in her bow is 20.0 meters above the ground and is aimed at an angle of \( 0^{\circ} \) relative to the ground. If the archer is trying to hit a target that lies on the ground 118 m away, with what initial velocity must she launch her arrow? (NOTE: The picture is not drawn to scale.)
26 27 28 29 30 31 32 33 34 35
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text

Enter your question here…

By image
Re-Upload
Uploaded Files
xxxx.png0%
Submit
📸 STUDY CAN BE A REAL STRUGGLE
Why Not UpStudy It?
Select your plan below
Premium

You can enjoy

  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to answer and
    solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic
  • Limited Solutions