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3 (a) Show graphically the geometric image of the complex number: \( |z+i| \geq 2 \)

Ask by Pritchard Wells. in Kenya
Jan 10,2025

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The geometric image of \( |z + i| \geq 2 \) is all points in the complex plane that are at least 2 units away from the point \( (0, -1) \). This includes the boundary of the circle centered at \( (0, -1) \) with a radius of 2.

Solution

To graphically represent the inequality \( |z + i| \geq 2 \) in the complex plane, let's break it down step by step. ### 1. Understanding the Expression Let \( z \) be a complex number represented as \( z = x + iy \), where: - \( x \) is the real part. - \( y \) is the imaginary part. The expression \( |z + i| \) represents the **distance** between the complex number \( z \) and the point \( -i \) in the complex plane. ### 2. Rewriting the Inequality Express \( |z + i| \) in terms of \( x \) and \( y \): \[ |z + i| = |x + iy + i| = |x + i(y + 1)| = \sqrt{x^2 + (y + 1)^2} \] So, the inequality \( |z + i| \geq 2 \) becomes: \[ \sqrt{x^2 + (y + 1)^2} \geq 2 \] ### 3. Squaring Both Sides To simplify, square both sides of the inequality: \[ x^2 + (y + 1)^2 \geq 4 \] ### 4. Geometric Interpretation This inequality represents all the points \( (x, y) \) in the complex plane that are **at least a distance of 2 units** away from the point \( (0, -1) \). Here's what this looks like: - **Center of the Circle**: \( (0, -1) \) - **Radius of the Circle**: \( 2 \) ### 5. Graphical Representation - **Draw the Complex Plane**: Plot the real axis (horizontal) and the imaginary axis (vertical). - **Locate the Center**: Mark the point \( (0, -1) \) on the imaginary axis. - **Draw the Circle**: With a radius of 2 units around \( (0, -1) \), draw a circle. - **Shade the Region**: Since the inequality is \( \geq 2 \), shade the entire **exterior** of the circle, including the boundary. ### 6. Visual Summary ``` Imaginary Axis (y) | | Exterior Region (|z + i| ≥ 2) | ___________ | / \ | / \ | / \ |_____/_________________\_____ Real Axis (x) (0, -1) ``` - **Circle**: Centered at \( (0, -1) \) with radius 2. - **Shaded Area**: All points outside and on the circle. ### 7. Interpretation - **Points Inside the Circle**: These satisfy \( |z + i| < 2 \) and are **not** included in the region defined by the inequality. - **Points On and Outside the Circle**: These satisfy \( |z + i| \geq 2 \) and are included in the region. ### 8. Conclusion The geometric image of \( |z + i| \geq 2 \) in the complex plane is the **set of all points lying on or outside a circle** centered at \( (0, -1) \) with a radius of 2 units.

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To visualize the inequality \( |z+i| \geq 2 \), we start by rewriting it in a more familiar form. The expression \( |z+i| \) indicates the distance of the complex number \( z \) from the point \( -i \) in the complex plane. This inequality describes the region outside or on the boundary of a circle with a radius of 2 centered at the point \( -i \). In the complex plane, the center of your circle is at the coordinates (0, -1), and the boundary of the circle is formed by the equation \( |z+i| = 2 \). Graphically, this will look like a circle with radius 2 extending upwards and downwards from the center point, indicating that all points outside of this circle (including those on the perimeter) satisfy the inequality. To clearly illustrate this, draw a vertical line representing the imaginary axis, mark the point \( -i \) below the origin, then sketch a circle with a radius of 2 units. Shade the area outside the circle to represent \( |z+i| \geq 2 \), while the interior remains unshaded. This outer region encompasses all complex numbers that fulfill the specified condition!

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