4. Which of the following points lies on the graph of \( y=x^{2}-5 \) ? \( \begin{array}{ll}\text { (1) }(3,-2) & \text { (3) }(5,0) \\ \text { (2) }(-2,-1) & \text { (4) }(-1,-6)\end{array} \)
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To determine which points lie on the graph of \( y = x^2 - 5 \), we need to substitute the x-values of each point into the equation and see if the resulting y-value matches the y-value of the point. 1. For the point \( (3, -2) \): \[ y = 3^2 - 5 = 9 - 5 = 4 \quad \text{(not -2)} \] 2. For the point \( (-2, -1) \): \[ y = (-2)^2 - 5 = 4 - 5 = -1 \quad \text{(this one matches!)} \] 3. For the point \( (5, 0) \): \[ y = 5^2 - 5 = 25 - 5 = 20 \quad \text{(not 0)} \] 4. For the point \( (-1, -6) \): \[ y = (-1)^2 - 5 = 1 - 5 = -4 \quad \text{(not -6)} \] Therefore, the point \((-2, -1)\) lies on the graph of \( y = x^2 - 5 \).