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5. Find a polynomial \( f(x) \) with a leading coefficient of 2 and a zero at -3 with multiplicity 2 and a zero at 4 with multiplicity 3 . Write your answer in complete factored form.

Ask by Christensen Allan. in Germany
Mar 13,2025

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The polynomial is \( f(x) = 2(x+3)^2(x-4)^3 \).

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To construct the polynomial \( f(x) \) with the given conditions, we start by expressing the zeros with their respective multiplicities. The zero at -3 has multiplicity 2, so its factor will be \( (x + 3)^2 \). The zero at 4 has multiplicity 3, leading to the factor \( (x - 4)^3 \). Putting it all together, we have the polynomial in factored form as follows: \[ f(x) = 2(x + 3)^2(x - 4)^3 \] This gives us a polynomial with a leading coefficient of 2, which satisfies all the given conditions.

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