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7. Find intervals of where \( f \) is increasing. \( r=4 \sin \theta \) inc:

Ask by Rodriquez Pritchard. in the United States
Mar 11,2025

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Answer

The function \( f(\theta) = 4\sin \theta \) is increasing when \( \cos \theta > 0 \), which occurs in the intervals \( \theta \in \left(0, \frac{\pi}{2}\right) \) and \( \theta \in \left(\frac{3\pi}{2}, 2\pi\right) \).

Solution

1. Write the function as \[ f(\theta)=4\sin \theta. \] 2. Compute the derivative with respect to \(\theta\): \[ f'(\theta)=4\cos \theta. \] 3. The function is increasing when its derivative is positive: \[ 4\cos \theta>0 \quad \Longleftrightarrow \quad \cos \theta>0. \] 4. The cosine function is positive for angles in the intervals \[ \theta\in\left(-\frac{\pi}{2}+2\pi k,\, \frac{\pi}{2}+2\pi k\right), \quad k\in\mathbb{Z}. \] If we restrict \(\theta\) to the interval \([0,2\pi)\), these intervals become: \[ \theta\in\left(0,\, \frac{\pi}{2}\right) \quad \text{and} \quad \theta\in\left(\frac{3\pi}{2},\,2\pi\right). \] 5. Therefore, the function \( f(\theta)=4\sin \theta \) is increasing when \[ \theta\in\left\{ \theta: \cos \theta>0 \right\} \quad \text{or, equivalently,} \quad \theta\in\left(-\frac{\pi}{2}+2\pi k,\, \frac{\pi}{2}+2\pi k\right) \text{ for any integer } k. \]

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The Deep Dive

To find the intervals where \( f \) is increasing for the polar function \( r = 4 \sin \theta \), we can express \( r \) in Cartesian coordinates. That gives us \( x^2 + y^2 = r^2 \) and \( y = r \sin \theta = 4 \sin^2 \theta \). By finding the derivative \(\frac{dy}{dx}\) and examining the sign of this derivative, we can determine the intervals where \( f \) is increasing. As a final touch, don't forget that in polar coordinates, the rounds where \( \theta \) increases (from 0 to \(\pi\)) correspond to regions where \( r \) grows larger in the direction it points. Keep those trigonometric identities handy! For instance, the function \( f \) is increasing in intervals where \( \sin \theta \) is positive, which happens in quadrants I and II (or for \(\theta \in (0, \pi)\)), promoting exploration of those angles!

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