\begin{tabular}{|l|}\hline\( \square \) Question 3 \\ If a Quadratic Function is written in \\ Standard Form, \( f(x)=a(x-h)^{2}+k \), the \( y^{-} \) \\ coordinate of the vertex represents the \\ opposite value of \( k \). \\ O True \\ O False \\ \hline\end{tabular}

The statement is False! In the standard form of a quadratic function \( f(x) = a(x-h)^2 + k \), the vertex of the parabola is indeed at the point \( (h, k) \). Therefore, the y-coordinate of the vertex is \( k \) itself, not its opposite value. So keep that \( k \) positive or negative, but it stays just as it is at the vertex! To further cement your knowledge, remember that the vertex represents either the lowest point (if \( a > 0 \)) or the highest point (if \( a < 0 \)) of the parabola. When graphing, the vertex is the crucial turning point, so you'll always want to identify it clearly to understand the shape of your quadratic function!