\[ \left(-3 x^{2}+5 x-2\right)-2\left(x^{2}-2 x-1\right) \] If the expression above is rewritten in the form \( a x^{2}+b x+c \), where \( a, b \), and \( c \) are constants, what is the value of \( b \) ? 30 ?
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To rewrite the given expression \( \left(-3 x^{2}+5 x-2\right)-2\left(x^{2}-2 x-1\right) \) in the form \( a x^{2}+b x+c \), we first distribute the \(-2\) across the second term: \[ -3x^2 + 5x - 2 - 2(x^2 - 2x - 1) = -3x^2 + 5x - 2 - 2x^2 + 4x + 2 \] Next, we combine like terms: \[ (-3x^2 - 2x^2) + (5x + 4x) + (-2 + 2) = -5x^2 + 9x + 0 \] Therefore, in the expression \( ax^2 + bx + c \), we have \( a = -5 \), \( b = 9 \), and \( c = 0 \). The value of \( b \) is \( 9 \).