Length of court \( =30,5 \mathrm{~m} \) Width of court \( =15,25 \mathrm{~m} \) Radius of semicircle \( =4,9 \mathrm{~m} \) Area of centre circle \( =0,64 \mathrm{~m}^{2} \) Ealculate the circumference of the centre circle

1. The area of a circle is given by \[ A = \pi r^2 \] Given that the area of the centre circle is \( A = 0.64 \, \mathrm{m}^2 \), we can find the radius \( r \) by solving \[ r = \sqrt{\frac{A}{\pi}} = \sqrt{\frac{0.64}{\pi}}. \] 2. The circumference \( C \) of a circle is calculated with \[ C = 2\pi r. \] Substitute the expression found for \( r \) into this formula: \[ C = 2\pi \sqrt{\frac{0.64}{\pi}}. \] 3. Simplify the expression by combining the factors: \[ C = 2\sqrt{0.64 \pi}. \] 4. To find a numerical approximation, first compute \[ 0.64 \pi \approx 0.64 \times 3.1416 \approx 2.010624. \] Then take the square root: \[ \sqrt{2.010624} \approx 1.418. \] And finally compute the circumference: \[ C \approx 2 \times 1.418 \approx 2.836 \, \mathrm{m}. \] 5. Therefore, the circumference of the centre circle is approximately \[ C \approx 2.84 \, \mathrm{m}. \]