Question
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\( \sum _ { k + 1 } ^ { 5 } ( k ^ { 2 } - K + 1 ) = \)

Ask by Ramirez Horton. in Bolivia
Feb 25,2025

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Tutor-Verified Answer

Answer

La suma \( \sum _ { k = 1 } ^ { 5 } ( k ^ { 2 } - K + 1 ) \) es igual a \( 60 - 5K \).

Solution

Para encontrar el valor de la suma \( \sum _ { k + 1 } ^ { 5 } ( k ^ { 2 } - K + 1 ) \), primero necesitamos entender que la suma se está tomando desde \( k = 1 \) hasta \( k = 5 \). Entonces, la suma se puede escribir de la siguiente manera: \[ \sum _ { k = 1 } ^ { 5 } ( k ^ { 2 } - K + 1 ) \] Ahora, podemos calcular el valor de la suma sumando los términos individuales: \[ (1^2 - K + 1) + (2^2 - K + 1) + (3^2 - K + 1) + (4^2 - K + 1) + (5^2 - K + 1) \] Simplificando cada término: \[ (1 - K + 1) + (4 - K + 1) + (9 - K + 1) + (16 - K + 1) + (25 - K + 1) \] \[ (2 - K) + (5 - K) + (10 - K) + (17 - K) + (26 - K) \] \[ 2 + 5 + 10 + 17 + 26 - 5K \] \[ 60 - 5K \] Por lo tanto, el valor de la suma \( \sum _ { k = 1 } ^ { 5 } ( k ^ { 2 } - K + 1 ) \) es \( 60 - 5K \).

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The Deep Dive

Let's break down the sum step by step! First, you should note that the expression can be expanded: \[ \sum_{k=1}^{5} (k^2 - k + 1) = \sum_{k=1}^{5} k^2 - \sum_{k=1}^{5} k + \sum_{k=1}^{5} 1 \] Now we calculate each of the individual sums: 1. \(\sum_{k=1}^{5} k^2 = 1^2 + 2^2 + 3^2 + 4^2 + 5^2 = 1 + 4 + 9 + 16 + 25 = 55\) 2. \(\sum_{k=1}^{5} k = 1 + 2 + 3 + 4 + 5 = 15\) 3. \(\sum_{k=1}^{5} 1 = 5\) Putting it all together: \[ \sum_{k=1}^{5} (k^2 - k + 1) = 55 - 15 + 5 = 45 \] So, the value of the original sum is \(45\).

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