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On a separate piece of paper, make a grouped frequency table using the intervals 141 to 150,151 to 160 and so on. Use the table to answer these questions. (i) In which interval did most of the students guess? (ii) How manv studentc'

Ask by Patel Montgomery. in the United Kingdom
Mar 08,2025

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Answer

Most students guessed in the interval \(151-160\), and 5 students made guesses in that range.

Solution

1. **Group the Data into Intervals**  a. List the intervals as specified. For example, if the guesses (or scores) lie between 141 and 190, you might form the following groups:   - \(141-150\)   - \(151-160\)   - \(161-170\)   - \(171-180\)   - \(181-190\) 2. **Tally the Data**  a. For each recorded guess (or value), place a tally mark in the appropriate interval.  b. Count the number of tally marks in each interval to obtain the frequency.  For example, suppose the completed grouped frequency table looks like: | Interval | Tally | Frequency | |--------------|--------------|-----------| | \(141-150\) | \(\vert\vert\) | 2 | | \(151-160\) | \(\vert\vert\vert\vert\vert\) | 5 | | \(161-170\) | \(\vert\vert\vert\) | 3 | | \(171-180\) | \(\vert\vert\) | 2 | | \(181-190\) | \(\vert\vert\vert\) | 3 | 3. **Answer the Questions**  (i) The question “In which interval did most of the students guess?” is answered by identifying the interval with the highest frequency. In the table above, the highest frequency is \(5\) in the interval \(151-160\).   Thus, the answer is:    “The most guesses occurred in the interval \(151-160\).”  (ii) The second part “How many students...” (presumably, “How many students guessed in the interval where most of the guesses occurred?”) is answered by reading the frequency for that interval.   In the table example, \(5\) students guessed in the interval \(151-160\). 4. **Summary of Answers**  \(\textbf{(i)}\) Most of the students guessed within the interval \(151-160\).  \(\textbf{(ii)}\) There were \(5\) students who guessed in that interval. *Note:* The numbers used in the example table are for illustration purposes. When you work with your actual data, replace the tally counts with those determined from your data to obtain the final answers.

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Bonus Knowledge

Creating a grouped frequency table is an excellent way to visualize data, particularly for identifying patterns or trends. To build the table, you would tally up the number of guesses that fall into the specified intervals (e.g., 141-150, 151-160, etc.). Use data points from your survey or results to determine how many students fall into each interval. After completing your frequency table, you can identify the interval with the highest frequency for question (i). This will show you where most students tended to guess. For question (ii), simply add up the frequencies of the groups to determine the total number of students who participated in the guessing game. It’s a straightforward process that highlights the collective guessing trends!

Related Questions

Question 12(Mulliple Choice Warth 5 points) \[ (04.06 \mathrm{HC}) \] A researcher wants to test the claim that the proportion of juniors who watch television regularly is greater than the proportion of seniors who watch television regularly She finds that 56 of 70 randomly selected juniors and 47 of 85 randomly selected seniors report watching television regularly. Construct \( 95 \% \) confidence intervals for each population proportion. Which of the statemente gives the correct outcome of the research or's tert of the dalim? The \( 95 \% \) confidence interval for juniors is (706, 894), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is (721, 879), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( 706,894 ), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( \( 721, .879 \) ), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors.

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