Part C-Extended-response question ( 6 marks) A florist wholesaler has a delivery of 1176 roses, 1260 tulips and 1350 gerberas from flower arowers. Write each number in prime factor form. Draw factor trees or use repeated divisions to find the factors.

**Roses (1176):** 1. Divide by 2:   \(1176 \div 2 = 588\) 2. Divide 588 by 2:   \(588 \div 2 = 294\) 3. Divide 294 by 2:   \(294 \div 2 = 147\)   Thus far, we have a factor of \(2^3\). 4. Divide 147 by 3:   \(147 \div 3 = 49\)   Now, include the factor \(3\). 5. Recognize that \(49 = 7 \times 7\), i.e.,   \(49 = 7^2\). 6. Therefore, the prime factorization is:   \(\displaystyle 1176 = 2^3 \times 3 \times 7^2\). --- **Tulips (1260):** 1. Divide by 2:   \(1260 \div 2 = 630\) 2. Divide 630 by 2:   \(630 \div 2 = 315\)   So, we have \(2^2\). 3. Divide 315 by 3:   \(315 \div 3 = 105\) 4. Divide 105 by 3:   \(105 \div 3 = 35\)   Now, include \(3^2\). 5. Factor 35 as:   \(35 = 5 \times 7\). 6. Therefore, the prime factorization is:   \(\displaystyle 1260 = 2^2 \times 3^2 \times 5 \times 7\). --- **Gerberas (1350):** 1. Divide by 2:   \(1350 \div 2 = 675\)   We have a factor of \(2\). 2. Divide 675 by 3:   \(675 \div 3 = 225\) 3. Divide 225 by 3:   \(225 \div 3 = 75\) 4. Divide 75 by 3:   \(75 \div 3 = 25\)   This gives \(3^3\). 5. Recognize that \(25 = 5 \times 5 = 5^2\). 6. Therefore, the prime factorization is:   \(\displaystyle 1350 = 2 \times 3^3 \times 5^2\).