In a second grade class containing 15 girls and 9 boys, 2 students are selected at random to give out the math papers. What is the probability that both are girls? Select one: O A. \( \frac{5}{8} \cdot \frac{15}{23} \) O B. \( \frac{5}{8} \cdot \frac{14}{23} \) O C. \( \frac{5}{8} \cdot \frac{5}{8} \) O D. \( \frac{3}{8} \cdot \frac{8}{23} \)

To find the probability that both selected students are girls, we start by determining the total number of students, which is \(15 + 9 = 24\). The probability that the first student chosen is a girl is \( \frac{15}{24} \) (or simplified, \( \frac{5}{8} \)). If the first chosen student is a girl, there are now 14 girls left and the total number of students becomes 23. Thus, the probability that the second student is also a girl is \( \frac{14}{23} \). Therefore, the probability that both are girls is: \[ \frac{15}{24} \times \frac{14}{23} = \frac{5}{8} \times \frac{14}{23} \] So, the correct answer is **B. \( \frac{5}{8} \cdot \frac{14}{23} \)**. Warm up your math skills by thinking about how probability works in real life! For instance, every time you pick a favorite snack from a mixed bag, you're using a form of probability to decide your delicious fate! Just remember, probabilities are all about understanding chances and making informed guesses! For further exploration, check out books on basic probabilities and fun games that involve chance. Titles like "The Joy of Probability" can make learning about this topic engaging, bringing these concepts to life through fun examples and vibrant illustrations!