Solve using substitution. \[ \begin{array}{l}y=-x-8 \\ y=3 x+4\end{array} \]
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To solve the system of equations using substitution, start by substituting the expression for \(y\) from the first equation into the second equation. This gives: \[-x - 8 = 3x + 4.\] Now, solve for \(x\) by moving all \(x\) terms to one side: \[-x - 3x = 4 + 8,\] \[-4x = 12,\] \[x = -3.\] Now that you have \(x\), substitute it back into the first equation to find \(y\): \[y = -(-3) - 8 = 3 - 8 = -5.\] Thus, the solution to the system of equations is \((x, y) = (-3, -5)\).