Solve using substitution. $$ \begin{array}{l}y=-x-8 \ y=3 x+4\end{array} $$

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Solve the system of equations $$ y=-x-8;y=3x+4 $$.
Solve the system of equations by following steps:
- step0: Solve using the substitution method:
  $$\left\{ \begin{array}{l}y=-x-8\y=3x+4\end{array}ight.$$
- step1: Substitute the value of $$y:$$
  $$-x-8=3x+4$$
- step2: Move the expression to the left side:
  $$-x-3x=4+8$$
- step3: Add and subtract:
  $$-4x=4+8$$
- step4: Add and subtract:
  $$-4x=12$$
- step5: Change the signs:
  $$4x=-12$$
- step6: Divide both sides:
  $$\frac{4x}{4}=\frac{-12}{4}$$
- step7: Divide the numbers:
  $$x=-3$$
- step8: Substitute the value of $$x:$$
  $$y=-\left(-3ight)-8$$
- step9: Substitute back:
  $$y=3-8$$
- step10: Calculate:
  $$y=-5$$
- step11: Calculate:
  $$\left\{ \begin{array}{l}x=-3\y=-5\end{array}ight.$$
- step12: Check the solution:
  $$\left\{ \begin{array}{l}x=-3\y=-5\end{array}ight.$$
- step13: Rewrite:
  $$\left(x,yight) = \left(-3,-5ight)$$
The solution to the system of equations using substitution is $$ (x,y) = (-3,-5) $$.
The solution is $$ x = -3 $$ and $$ y = -5 $$.

Solve using substitution. \[ \begin{array}{l}y=-x-8 \\ y=3 x+4\end{array} \]

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