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A paper label just covers the curved surface area of a cylindrical tin of diameter 16 cm and height \( 17 \frac{1}{2} \mathrm{~cm} \). Calculate the area of the label.

Ask by Hodgson Evans. in Nigeria
Mar 09,2025

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The area of the label is approximately 879.65 cm².

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To calculate the area of the label covering the curved surface area of the cylindrical tin, we'll use the formula for the curved surface area (CSA) of a cylinder given by: \[ \text{CSA} = 2\pi rh \] where \( r \) is the radius and \( h \) is the height of the cylinder. 1. **Calculate the radius**: Since the diameter is given as 16 cm, the radius \( r \) is: \[ r = \frac{16}{2} = 8 \text{ cm} \] 2. **Convert the height into an improper fraction**: The height is given as \( 17 \frac{1}{2} \) cm, which is: \[ 17 \frac{1}{2} = \frac{35}{2} \text{ cm} \] 3. **Now substitute the values into the CSR formula**: \[ \text{CSA} = 2\pi (8) \left(\frac{35}{2}\right) \] 4. **Simplify the equation**: \[ \text{CSA} = 2\pi (8) \left(\frac{35}{2}\right) = 8 \times 35 \times \pi = 280\pi \] 5. **Approximate using \( \pi \approx 3.14 \)**: \[ 280\pi \approx 280 \times 3.14 = 879.2 \text{ cm}^2 \] Thus, the area of the label is approximately \( 879.2 \text{ cm}^2 \).

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