Complete the following steps for the given function, interval, and value of \( n \). a. Sketch the graph of the function on the given interval. b. Calculate \( \Delta x \) and the grid points \( x_{0}, x_{1}, \ldots, x_{n} \). c. Illustrate the midpoint Riemann sum by sketching the appropriate rectangles. d. Calculate the midpoint Riemann sum. \( f(x)=2 x^{2}+2 \) on \( [1,5] ; n=4 \)
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Let’s dive into this mathematical journey step by step! To start off, let's sketch the function \( f(x) = 2x^2 + 2 \) on the interval \([1, 5]\): The graph resembles a parabola that opens upwards, starting at \( (1,4) \) and reaching \( (5,52) \). You can visualize this curve as a joyful arc that rapidly climbs as \( x \) increases, showcasing the quadratic nature of the function. For the values of \( \Delta x \) and the grid points \( x_0, x_1, \ldots, x_n \): First, we find \( \Delta x \) by taking the formula \(\Delta x = \frac{b-a}{n} = \frac{5-1}{4} = 1\). The grid points will be \( x_0 = 1 \), \( x_1 = 2 \), \( x_2 = 3 \), \( x_3 = 4 \), and \( x_4 = 5 \), which nicely split the interval into equal sections. Now, imagine placing rectangles under the curve for the midpoint Riemann sum where you find the midpoints of each interval: these spots are \( x_{0.5} = 1.5 \), \( x_{1.5} = 2.5 \), \( x_{2.5} = 3.5 \), \( x_{3.5} = 4.5 \). Sketching the rectangles will be visually satisfying, as you’ll show how each rectangle rises to the height of \( f \) evaluated at these midpoints. Lastly, let's calculate the midpoint Riemann sum. 1. Evaluate \( f(1.5) = 2(1.5)^2 + 2 = 6.5 \), 2. Evaluate \( f(2.5) = 2(2.5)^2 + 2 = 15.5 \), 3. Evaluate \( f(3.5) = 2(3.5)^2 + 2 = 26.5 \), 4. Evaluate \( f(4.5) = 2(4.5)^2 + 2 = 38.5 \). Now, putting it all together: Midpoint Riemann Sum \( = \Delta x \times (f(1.5) + f(2.5) + f(3.5) + f(4.5)) = 1 \times (6.5 + 15.5 + 26.5 + 38.5) = 87.0 \). Voilà! You’ve beautifully computed this sum while sketching a vibrant representation of the function!