e angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately \( 13.8^{\circ} \). If skyscraper s 1469 feet tall, how far apart are the two skyscrapers? Assume the bases of the two buildings are at the same vation. he distance from skyscraper \( A \) to skyscraper \( B \) is \( \square \) feet.

To find the distance between the two skyscrapers, we can use the tangent function from trigonometry. Given: - Angle of inclination from the base of skyscraper A to the top of skyscraper B: \( 13.8^{\circ} \) - Height of skyscraper A: 1469 feet We can use the tangent function to find the distance between the two skyscrapers. The tangent function is defined as: \[ \tan(\theta) = \frac{\text{opposite side}}{\text{adjacent side}} \] In this case, the opposite side is the height of skyscraper A (1469 feet), and the adjacent side is the distance between the two skyscrapers (which we want to find). Let's denote the distance between the two skyscrapers as \( d \). Using the tangent function, we have: \[ \tan(13.8^{\circ}) = \frac{1469}{d} \] Now, we can solve for \( d \) by rearranging the equation: \[ d = \frac{1469}{\tan(13.8^{\circ})} \] Let's calculate the value of \( d \) using the tangent function. The distance between the two skyscrapers is approximately 514.96 feet.