Write a polynomial $$ f(x) $$ that meets the given conditions. Answers may vary. Degree 2 polynomial with zeros of $$ 2 \sqrt{15} $$ and $$ -2 \sqrt{15} $$. $$ f(x)=\square $$

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1. Since the polynomial is of degree 2 and has zeros $$2\sqrt{15}$$ and $$-2\sqrt{15}$$, we can write it in its factored form as:
   $$
   f(x) = a \left(x - 2\sqrt{15}\right)\left(x + 2\sqrt{15}\right)
   $$

2. If we choose $$a = 1$$ for simplicity (i.e., a monic polynomial), then:
   $$
   f(x) = \left(x - 2\sqrt{15}\right)\left(x + 2\sqrt{15}\right)
   $$

3. We expand the product using the difference of squares:
   $$
   f(x) = x^2 - \left(2\sqrt{15}\right)^2 = x^2 - 4 \cdot 15 = x^2 - 60
   $$

Thus, one possible polynomial is:
$$
f(x) = x^2 - 60
$$
One possible polynomial is $$ f(x) = x^2 - 60 $$.

Write a polynomial \( f(x) \) that meets the given conditions. Answers may vary. Degree 2 polynomial with zeros of \( 2 \sqrt{15} \) and \( -2 \sqrt{15} \). \( f(x)=\square \)

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