Write a polynomial \( f(x) \) that meets the given conditions. Answers may vary. Degree 2 polynomial with zeros of \( 2 \sqrt{15} \) and \( -2 \sqrt{15} \). \( f(x)=\square \)

To create a degree 2 polynomial with the given zeros \( 2\sqrt{15} \) and \( -2\sqrt{15} \), we can use the fact that if \( r_1 \) and \( r_2 \) are the roots, then the polynomial can be expressed in the form \( f(x) = k (x - r_1)(x - r_2) \). Here, let's choose \( k = 1 \) for simplicity: \[ f(x) = (x - 2\sqrt{15})(x + 2\sqrt{15}). \] Using the difference of squares formula, this simplifies to: \[ f(x) = x^2 - (2\sqrt{15})^2 = x^2 - 4 \cdot 15 = x^2 - 60. \] So, the polynomial is: \[ f(x) = x^2 - 60. \]