Find the discriminant. \[ x^{2}+4 x+4=0 \] Save answer

To find the discriminant of the quadratic equation \( x^2 + 4x + 4 = 0 \), you can use the formula \( D = b^2 - 4ac \), where \( a \), \( b \), and \( c \) are the coefficients from the standard form \( ax^2 + bx + c \). Here, \( a = 1 \), \( b = 4 \), and \( c = 4 \). Now, plug the values into the formula: \[ D = 4^2 - 4 \cdot 1 \cdot 4 = 16 - 16 = 0. \] So, the discriminant is \( D = 0 \). This indicates that the quadratic has exactly one real solution (or a repeated root).