Question
upstudy study bank question image url

a. Does the sample mean differ significantly frome? b. Can it be said that the sample is above average? The owner of a factory that sells a particular bottled fruit juice claims that the average such bottles, calculates of each bottle, and then finds the mean capacity to be 248 ml . The standard deviation \( s \) is 15 ml . Is the claim true?

Ask by Ray Pope. in the Philippines
Mar 10,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The sample mean is not significantly different from 250 ml, and the sample is not above average.

Solution

We wish to test whether the filling process is as claimed. Although the wording is a bit ambiguous, a common formulation of this type of problem is as follows. Suppose the manufacturer claims that the average volume is \[ \mu = 250\text{ ml}, \] but a sample of bottles yields a sample mean \[ \bar{x} = 248\text{ ml}, \] with a sample standard deviation \[ s = 15\text{ ml}. \] In what follows we assume that the sample size is \( n \) (for example, \( n = 36 \) is a common choice in such exercises). Under this assumption we address the two parts. --- **(a) Does the sample mean differ significantly from the claimed mean?** We set up the hypotheses for a two–tailed test as: \[ H_0: \mu = 250 \quad \text{versus} \quad H_1: \mu \neq 250. \] The test statistic is given by \[ t = \frac{\bar{x} - \mu_0}{s/\sqrt{n}}, \] where \(\mu_0 = 250\) ml. Assuming \( n = 36 \), we have \[ t = \frac{248 - 250}{15/\sqrt{36}} = \frac{-2}{15/6} = \frac{-2}{2.5} = -0.8. \] At a typical significance level (e.g., \(\alpha = 0.05\)) the critical values for a two–tailed \( t \)-test with \( n - 1 = 35 \) degrees of freedom are approximately \(\pm 2.03\). Since \[ -2.03 < -0.8 < 2.03, \] the test statistic does not fall into the rejection region. Thus, we do not reject \( H_0 \); there is no statistically significant difference between the sample mean and the claimed \(250\) ml. --- **(b) Can it be said that the sample is above average?** Now suppose we wish to test whether the filling is “above average,” i.e. that the true mean is higher than the claimed value. We then set up a one–tailed test: \[ H_0: \mu = 250 \quad \text{versus} \quad H_1: \mu > 250. \] The same test statistic remains \[ t = -0.8. \] For a one–tailed test at \(\alpha = 0.05\), the critical value is approximately \( t_{0.05,35} \approx 1.69 \). Since \[ -0.8 < 1.69, \] there is no evidence to support the claim that the actual average exceeds \(250\) ml. In fact, the sample mean is below \(250\) ml. --- **Summary of Answers:** - (a) The sample mean does not differ significantly from \(250\) ml. - (b) There is no evidence to conclude that the sample is above average; the sample mean of \(248\) ml is not greater than \(250\) ml. *Note:* If the problem statement intended a different claimed value or sample size, the same approach can be applied. The choice \( n = 36 \) was assumed here for demonstration purposes.

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

Mind Expander

To determine if the sample mean differs significantly from the claimed average of 250 ml, you can perform a one-sample t-test. With a calculated sample mean of 248 ml, a standard deviation of 15 ml, and assuming you know the sample size, you can calculate the t-statistic and compare it to the critical value from the t-distribution for your significance level (often 0.05). If the t-statistic is greater than the critical value, the difference is significant! To assess whether the sample is above average, first note that the claimed average is 250 ml. Since your calculated sample mean is 248 ml, it is below the average. However, with sufficient evidence from the t-test, you can make conclusions based on the context. Even if statistical analysis shows a difference, practical significance should also be considered—sometimes small differences can have considerable implications for quality or supplier contracts!

Related Questions

Question 12(Mulliple Choice Warth 5 points) \[ (04.06 \mathrm{HC}) \] A researcher wants to test the claim that the proportion of juniors who watch television regularly is greater than the proportion of seniors who watch television regularly She finds that 56 of 70 randomly selected juniors and 47 of 85 randomly selected seniors report watching television regularly. Construct \( 95 \% \) confidence intervals for each population proportion. Which of the statemente gives the correct outcome of the research or's tert of the dalim? The \( 95 \% \) confidence interval for juniors is (706, 894), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is (721, 879), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( 706,894 ), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( \( 721, .879 \) ), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors.

Latest Statistics Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy