x) \( =\lim _{x \rightarrow-1^{-}}\left(x^{2}-2 \ln x+9\right)= \)

To evaluate the limit \( \lim _{x \rightarrow-1^{-}}\left(x^{2}-2 \ln x+9\right) \), we first check the components as \( x \) approaches \(-1\) from the left. The term \( x^2 \) approaches \( 1 \), but the \( \ln x \) term poses a problem since the natural logarithm is not defined for negative values. As \( x \) approaches \(-1^{-}\), \( \ln x \) approaches negative infinity, leading the entire expression towards positive infinity. Therefore, the limit diverges and the final outcome is \( +\infty \). So, we conclude: \[ \lim _{x \rightarrow-1^{-}}\left(x^{2}-2 \ln x+9\right) = +\infty \]