Question
Find the \( x \)-intercept and \( y \)-intercept of the line. \( 6 x-7 y=-10 \) \( y \)-intercept: \( \square \)
Ask by Byrd Bowman. in the United States
Mar 14,2025
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Answer
The \( y \)-intercept is at \( \left(0, \frac{10}{7}\right) \) and the \( x \)-intercept is at \( \left(-\frac{5}{3}, 0\right) \).
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To find the \( x \)-intercept, set \( y = 0 \) in the equation \( 6x - 7y = -10 \). This gives us \( 6x = -10 \), leading to \( x = -\frac{5}{3} \). Thus, the \( x \)-intercept is \( -\frac{5}{3} \) or the point \( \left(-\frac{5}{3}, 0\right) \). For the \( y \)-intercept, set \( x = 0 \) in the same equation. This gives \( -7y = -10 \), resulting in \( y = \frac{10}{7} \). So, the \( y \)-intercept is \( \frac{10}{7} \) or the point \( (0, \frac{10}{7}) \).