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11. In \( \triangle V W X, v=85 \mathrm{~cm}, x=58 \mathrm{~cm} \) and \( \angle X=107^{\circ} \). Find all possible values of \( \angle V \), to the nearest degree.

Ask by Wright Ryan. in the United States
Feb 25,2025

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Answer

The possible values of \( \angle V \) are \( 16^\circ \) and \( 164^\circ \).

Solution

To find the possible values of \( \angle V \) in triangle \( \triangle V W X \) given the sides \( v = 85 \, \text{cm} \), \( x = 58 \, \text{cm} \), and the angle \( \angle X = 107^\circ \), we can use the Law of Sines. The Law of Sines states that: \[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \] In our case, we can denote: - \( a = v = 85 \, \text{cm} \) - \( b = x = 58 \, \text{cm} \) - \( C = \angle X = 107^\circ \) - \( A = \angle V \) - \( B = \angle W \) Using the Law of Sines, we can write: \[ \frac{v}{\sin V} = \frac{x}{\sin X} \] Substituting the known values: \[ \frac{85}{\sin V} = \frac{58}{\sin 107^\circ} \] Now, we can solve for \( \sin V \): \[ \sin V = \frac{85 \cdot \sin 107^\circ}{58} \] Next, we need to calculate \( \sin 107^\circ \) and then find \( \sin V \). Let's perform the calculations. Calculate the value by following steps: - step0: Calculate: \(\sin\left(107\right)\) Calculate or simplify the expression \( (85 * 0.184782) / 58 \). Calculate the value by following steps: - step0: Calculate: \(\frac{\left(85\times 0.184782\right)}{58}\) - step1: Remove the parentheses: \(\frac{85\times 0.184782}{58}\) - step2: Multiply the numbers: \(\frac{15.70647}{58}\) - step3: Convert the expressions: \(\frac{\frac{1570647}{100000}}{58}\) - step4: Multiply by the reciprocal: \(\frac{1570647}{100000}\times \frac{1}{58}\) - step5: Multiply the fractions: \(\frac{1570647}{100000\times 58}\) - step6: Multiply: \(\frac{1570647}{5800000}\) We have calculated \( \sin 107^\circ \approx 0.184782 \). Now, substituting this value into our equation for \( \sin V \): \[ \sin V = \frac{85 \cdot 0.184782}{58} \approx 0.270801 \] Next, we need to find \( \angle V \) by taking the inverse sine: \[ V = \sin^{-1}(0.270801) \] Let's calculate \( V \). Calculate the value by following steps: - step0: Calculate: \(\arcsin\left(0.270801\right)\) Calculate or simplify the expression \( \arcsin(0.270801) \). Calculate the value by following steps: - step0: Calculate: \(\arcsin\left(0.270801\right)\) Calculate or simplify the expression \( 0.274225 * (180 / \pi) \). Calculate the value by following steps: - step0: Calculate: \(0.274225\times \frac{180}{\pi }\) - step1: Convert the expressions: \(\frac{10969}{40000}\times \frac{180}{\pi }\) - step2: Multiply the fractions: \(\frac{10969\times 180}{40000\pi }\) - step3: Multiply the terms: \(\frac{1974420}{40000\pi }\) - step4: Reduce the fraction: \(\frac{98721}{2000\pi }\) We found that: \[ V \approx 15.71^\circ \] However, since the sine function is positive in both the first and second quadrants, there is a possibility for another angle \( V' \): \[ V' = 180^\circ - V \approx 180^\circ - 15.71^\circ \approx 164.29^\circ \] Thus, the possible values for \( \angle V \) to the nearest degree are: 1. \( \angle V \approx 16^\circ \) 2. \( \angle V' \approx 164^\circ \) In conclusion, the possible values of \( \angle V \) are \( 16^\circ \) and \( 164^\circ \).

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Beyond the Answer

To solve for angle \( V \) in triangle \( VWX \), we can use the Law of Cosines. The formula states: \[ c^2 = a^2 + b^2 - 2ab \cdot \cos(C) \] In this case: - \( a = v = 85 \, \text{cm} \) - \( b = x = 58 \, \text{cm} \) - \( C = \angle X = 107^{\circ} \) First, let's find the length of side \( w \) (the side opposite angle \( V \)): \[ w^2 = v^2 + x^2 - 2 \cdot v \cdot x \cdot \cos(X) \] \[ w^2 = 85^2 + 58^2 - 2 \cdot 85 \cdot 58 \cdot \cos(107^{\circ}) \] \[ w^2 = 7225 + 3364 - 2 \cdot 85 \cdot 58 \cdot (-0.2924) \quad (\text{using } \cos(107^{\circ}) \approx -0.2924) \] \[ w^2 = 10589 + 85 \cdot 58 \cdot 0.5848 \] Calculating \( 85 \cdot 58 \cdot 0.5848 \): \[ 85 \cdot 58 \approx 4930 \] \[ 4930 \cdot 0.5848 \approx 2882.5 \] Now adding to calculate \( w^2 \): \[ w^2 \approx 10589 + 2882.5 \approx 13471.5 \implies w \approx 116 \, \text{cm} \] Now, let's find angle \( V \) using the Law of Sines: \[ \frac{v}{\sin(V)} = \frac{w}{\sin(X)} \] Rearranging gives: \[ \sin(V) = \frac{v \cdot \sin(X)}{w} \] Substituting the values: \[ \sin(V) = \frac{85 \cdot \sin(107^{\circ})}{116} \] Calculating \( \sin(107^{\circ}) \approx 0.9511 \): \[ \sin(V) = \frac{85 \cdot 0.9511}{116} \approx \frac{80.85}{116} \approx 0.696 \implies V \approx \arcsin(0.696) \approx 44^{\circ} \] However, since \( \sin \) can have two solutions, we must also consider the supplementary angle: \[ V' = 180^{\circ} - 44^{\circ} \approx 136^{\circ} \] Thus, the possible values for \( \angle V \) are \( 44^{\circ} \) and \( 136^{\circ} \).

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