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6. \( 121 \mathrm{a}^{6}-144 \mathrm{~b}^{\mathrm{a}} \) 7. \( \mathrm{x}^{3}-27 \) 8. \( 8 \mathrm{y}^{3}+125 \) 9. \( 216 \mathrm{a}^{9}-343 \mathrm{~b}^{6} \) 10. \( \mathrm{x}^{2}-10 \mathrm{x}+25 \) 11. \( 36 \mathrm{y}^{2}+60 \mathrm{y}+25 \) 12. \( 81 \mathrm{a}^{4}-108 \mathrm{a}^{2} \mathrm{~b}+36 \mathrm{~b}^{2} \) 13. \( \mathrm{x}^{2}+9 \mathrm{x}+20 \) 14. \( \mathrm{x}^{2}-3 \mathrm{x}-40 \) 15. \( \mathrm{x}^{2}-15 \mathrm{x}+56 \) 16. \( 3 \mathrm{x}^{2}+10 \mathrm{x}+7 \) 17. \( 5 \mathrm{x}^{2}-17 \mathrm{x}+6 \) 18. \( 18 \mathrm{x}^{2}-33 \mathrm{x}+14 \)

Ask by Huff Bush. in Mexico
Mar 12,2025

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Answer

Aquí están las factorizaciones de las expresiones: 6. \( 121 a^{6}-144 b^{a} \) No se pudo factorizar. 7. \( x^{3}-27 \) \( (x-3)(x^{2}+3x+9) \) 8. \( 8 y^{3}+125 \) \( (2y+5)(4y^{2}-10y+25) \) 9. \( 216 a^{9}-343 b^{6} \) \( (6a^{3}-7b^{2})(36a^{6}+42a^{3}b^{2}+49b^{4}) \) 10. \( x^{2}-10 x+25 \) \( (x-5)^{2} \) 11. \( 36 y^{2}+60 y+25 \) \( (6y+5)^{2} \) 12. \( 81 a^{4}-108 a^{2} b+36 b^{2} \) \( 9(3a^{2}-2b)^{2} \) 13. \( x^{2}+9 x+20 \) \( (x+4)(x+5) \) 14. \( x^{2}-3 x-40 \) \( (x-8)(x+5) \) 15. \( x^{2}-15 x+56 \) \( (x-8)(x-7) \) 16. \( 3 x^{2}+10 x+7 \) \( (x+1)(3x+7) \) 17. \( 5 x^{2}-17 x+6 \) \( (x-3)(5x-2) \) 18. \( 18 x^{2}-33 x+14 \) \( (3x-2)(6x-7) \) Si necesitas más ayuda con alguna de estas factorizaciones, no dudes en preguntar.

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Bonus Knowledge

The expression \( 121 a^6 - 144 b^2 \) can be factored using the difference of squares: \( (11 a^3 - 12 b)(11 a^3 + 12 b) \). This technique is great for recognizing patterns in polynomial equations and can help streamline problem-solving in algebra. When dealing with \( x^3 - 27 \), it's helpful to know that it represents a difference of cubes. This can be factored as \( (x - 3)(x^2 + 3x + 9) \). Understanding the special factorizations like difference of cubes can make polynomial expressions much easier to navigate and simplify!

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