Length of court \( =30,5 \mathrm{~m} \) Width of court \( =15,25 \mathrm{~m} \) Radius of semicircle \( =4,9 \mathrm{~m} \) Area of centre circle \( =0,64 \mathrm{~m}^{2} \) -alculate the circumference of the centre circle

Given that the area of the centre circle is \[ A = 0.64\,\text{m}^2, \] we start with the formula for the area of a circle: \[ A = \pi r^2. \] **Step 1. Solve for the radius \( r \):** \[ r^2 = \frac{A}{\pi} = \frac{0.64}{\pi}, \] \[ r = \sqrt{\frac{0.64}{\pi}}. \] **Step 2. Write the formula for the circumference \( C \):** \[ C = 2\pi r. \] **Step 3. Substitute the expression for \( r \) into the circumference formula:** \[ C = 2\pi \sqrt{\frac{0.64}{\pi}}. \] Simplify the expression: \[ C = 2\sqrt{0.64\,\pi} = 2(0.8)\sqrt{\pi} = 1.6\sqrt{\pi}. \] **Step 4. Calculate the numerical value:** Using \(\pi \approx 3.1416\), we have \[ \sqrt{\pi} \approx \sqrt{3.1416} \approx 1.772. \] Thus, \[ C \approx 1.6 \times 1.772 \approx 2.835. \] Therefore, the circumference of the centre circle is approximately \[ \boxed{2.84\,\text{m}}. \]