(a) The best point estimate of the mean is 29 pounds. Part: \( 1 / 4 \) Part 2 of 4 (b) Find the \( 90 \% \) confidence interval of the mean of these pounds. Round intermediate answers to at least three decimal places. Round your final answers to one decimal place. ( \( \quad \),

To construct a \( 90\% \) confidence interval for the mean based on the point estimate of \( 29 \) pounds, you'll first need the standard deviation and sample size. Assuming you have that info, you could use the formula: \[ \text{Confidence Interval} = \text{Point Estimate} \pm z^* \cdot \left( \frac{s}{\sqrt{n}} \right) \] Here, \( z^* \) is the z-value that corresponds to \( 90\% \) confidence (approximately \( 1.645 \)), \( s \) is the standard deviation, and \( n \) is the sample size. Plug in your values, perform the calculations and you'll yield two bounds for your confidence interval! Now, be sure to double-check that the assumptions for using a normal distribution hold true, like if your sample size is large enough or if the population from which the sample is drawn is normally distributed. It’s the best way to avoid any statistical traps!