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The SI units for \( k \), the spring constant, are equivalent to: 1) J . 2) \( \mathrm{J} / \mathrm{N} \). 3) \( \mathrm{kg} / \mathrm{s}^{2} \). 4) \( \mathrm{kg} / \mathrm{s} \). 5) None of the above.

Ask by Lane Norris. in the United States
Feb 25,2025

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Answer

The SI units for \( k \) are \( \mathrm{kg} / \mathrm{s}^{2} \).

Solution

The spring constant k is defined by Hooke’s Law, F = kx, where F is in newtons (N) and x is in meters (m). Rearranging gives k = F/x, so its SI units are N/m. Since 1 newton (N) equals 1 kg·m/s², substituting gives:   k = N/m = (kg·m/s²)/m = kg/s². Thus, the SI units for k are equivalent to kg/s². The correct answer is option 3.

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The spring constant \( k \) is defined by Hooke's law as \( F = kx \), where \( F \) is the force applied to compress or extend the spring, and \( x \) is the displacement from the equilibrium position. Force is measured in Newtons (N), and displacement in meters (m). Rearranging the equation gives \( k = \frac{F}{x} \); therefore, the units of \( k \) are given as \( \mathrm{N/m} \), which can be further broken down into \( \mathrm{kg} / \mathrm{s}^{2} \) because \( \mathrm{N} = \mathrm{kg} \cdot \mathrm{m/s}^2 \). To further explore the concept of spring constants, it's fascinating to learn about different types of springs used in engineering and their applications. From compression springs in mechanical systems to torsion springs in watches, the spring constant plays a critical role in determining the behavior of these systems under load. Understanding how different materials affect the spring constant can lead to innovations in design and engineering!

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