b) Draw triangle $$ X Y Z $$. The measure of $$ \angle X $$ is $$ 60^{\circ} $$. The measure of $$ \angle Y $$ is $$ 50^{\circ} $$. The length of side $$ X Y $$ is 5 cm .

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To draw triangle $$ XYZ $$ with the given conditions, we can follow these steps:

1. **Identify the Angles and Side**:
   - $$ \angle X = 60^{\circ} $$
   - $$ \angle Y = 50^{\circ} $$
   - The length of side $$ XY = 5 $$ cm.

2. **Calculate the Third Angle**:
   The sum of the angles in a triangle is $$ 180^{\circ} $$. Therefore, we can find $$ \angle Z $$ as follows:
   $$
   \angle Z = 180^{\circ} - \angle X - \angle Y = 180^{\circ} - 60^{\circ} - 50^{\circ} = 70^{\circ}
   $$

3. **Draw the Triangle**:
   - Start by drawing line segment $$ XY $$ which is 5 cm long.
   - At point $$ X $$, use a protractor to measure $$ 60^{\circ} $$ and draw a line extending from $$ X $$.
   - At point $$ Y $$, measure $$ 50^{\circ} $$ and draw another line extending from $$ Y $$.
   - The intersection of these two lines will be point $$ Z $$.

4. **Label the Triangle**:
   - Label the vertices as $$ X $$, $$ Y $$, and $$ Z $$.
   - Mark the angles $$ \angle X $$, $$ \angle Y $$, and $$ \angle Z $$ accordingly.

This process will give you a triangle $$ XYZ $$ with the specified angles and side length. If you need a visual representation, I can provide a plot of the triangle based on these specifications. Would you like me to do that?
To draw triangle $$ XYZ $$: 1. Draw side $$ XY $$ of 5 cm. 2. At point $$ X $$, draw $$ \angle X = 60^{\circ} $$. 3. At point $$ Y $$, draw $$ \angle Y = 50^{\circ} $$. 4. The intersection of these lines is point $$ Z $$. 5. Label the triangle with the given angles and side.

b) Draw triangle \( X Y Z \). The measure of \( \angle X \) is \( 60^{\circ} \). The measure of \( \angle Y \) is \( 50^{\circ} \). The length of side \( X Y \) is 5 cm .

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