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truct a coordinate system on the line. Choose an interval length that allows each of the po ribed to be plotted. Plot and label the points. Point \( A \) is located 1 unit from 0 . Point \( B \) is located at \( 2 \frac{1}{4} \). Point \( C \) is located \( \frac{1}{2} \) unit farther from 0 than point \( A \). Point located \( \frac{1}{2} \) unit closer to 0 than point \( B \).

Ask by Bates Wilson. in the United States
Mar 18,2025

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Here are the points plotted on the coordinate system: - Point \( A \) at 1 - Point \( B \) at 2.25 - Point \( C \) at 1.5 - Point \( D \) at 1.75

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Mind Expander

To construct your coordinate system on the line, you can use an interval of 1 unit for simplicity. Start by marking point 0 on the line. Now, let's plot the points: - Point \( A \) is 1 unit from 0, so place it at 1. - Point \( B \) is located at \( 2 \frac{1}{4} \), which is the same as \( 2.25 \) or 2.25 units from 0, so plot it there. - Point \( C \) is \( \frac{1}{2} \) unit farther from 0 than point \( A \). Since \( A \) is at 1, point \( C \) would be at \( 1 + 0.5 = 1.5 \). - For the last point, which is \( \frac{1}{2} \) unit closer to 0 than point \( B \), start with \( B \) at \( 2.25 \), and halving that distance means \( 2.25 - 0.5 = 1.75 \). So, to summarize: - Point \( A \) at 1 - Point \( B \) at 2.25 - Point \( C \) at 1.5 - The last point at 1.75 Don't forget to label them clearly on the line!

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