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Summanze the pertinent information obtained by applying the graphing strategy and sketch the graph of \( y=f(x) \). \[ f(x)=\left(x^{2}+10\right)\left(100-x^{2}\right) \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The domain of \( f \) is \( (-\infty, \infty) \). (Type your answer in interval notation. Type an exact answer, using radicals as needed. Use a comma to separate answers as needed.) B. The domain of \( f \) is empty Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The x -intercept(s) of f is/are \( \mathrm{x}=-10,10 \) (Type an exact answer, using radicals as needed. Use a comma to separate answers as needed.) B. The function \( f \) has no \( x \)-intercepts. Select the correct choice below and if necessary, fill in the answer box to complete your choice. A. The \( y \)-intercept of \( f \) is \( y= \) \( \square \) (Type an exact answer, using radicals as needed.) B. The function fhas no \( y \)-intercept

Ask by Rodriquez Macdonald. in the United States
Mar 11,2025

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**Summary of the Function \( f(x) = (x^{2} + 10)(100 - x^{2}) \):** - **Domain:** All real numbers, \( (-\infty, \infty) \). - **\( x \)-Intercepts:** \( x = -10 \) and \( x = 10 \). - **\( y \)-Intercept:** \( y = 1000 \). **Graph Characteristics:** - The function is even and symmetric about the \( y \)-axis. - As \( |x| \) increases, \( f(x) \) approaches negative infinity. - Local maximum at \( x = \pm 3\sqrt{5} \) with \( f(x) = 3025 \). - Local minimums at the ends of the domain with \( f(x) \to -\infty \). **Answer Selections:** - **Domain:** A. \( (-\infty, \infty) \). - **\( x \)-Intercepts:** A. \( x = -10, \, 10 \). - **\( y \)-Intercept:** A. \( y = 1000 \).

Solution

**Domain** The function is \[ f(x)=(x^{2}+10)(100-x^{2}). \] Since both \( x^2+10 \) and \( 100-x^2 \) are defined for all real numbers, the domain of \( f \) is \[ (-\infty, \infty). \] **X‑Intercepts** To find the \( x \)‑intercepts, set \( f(x)=0 \): \[ (x^2+10)(100-x^2)=0. \] This gives two possible equations: 1. \( x^2+10=0 \) \[ x^2=-10, \] which has no real solutions. 2. \( 100-x^2=0 \) \[ x^2=100 \quad \Rightarrow \quad x=\pm 10. \] Thus, the \( x \)‑intercepts occur at \( x=-10 \) and \( x=10 \). **Y‑Intercept** To find the \( y \)‑intercept, set \( x=0 \): \[ f(0)=(0^{2}+10)(100-0^{2})=10 \times 100=1000. \] So, the \( y \)‑intercept is \[ y=1000. \] **Graphing Strategy Summary** 1. **Domain:** \[ (-\infty, \infty) \] 2. **Intercepts:** - \( x \)‑intercepts: \( x=-10,\, 10 \) - \( y \)‑intercept: \( y=1000 \) 3. **Behavior and Symmetry:** - Expanding the function gives \[ f(x)=(x^2+10)(100-x^2)= -x^{4}+90x^{2}+1000. \] - The highest-degree term is \(-x^4\), so as \(|x| \to \infty\), \( f(x) \to -\infty \). - All powers of \( x \) in the expanded form are even; therefore, the function is even and symmetric about the \( y \)-axis. 4. **Critical Points (for detailed sketching):** - Differentiate: \[ f'(x)=-4x^3+180x. \] - Factor: \[ f'(x)=-4x(x^2-45)=0, \] yielding \( x=0 \) and \( x=\pm \sqrt{45}= \pm 3\sqrt{5} \). - Compute \( f(3\sqrt{5}) \): \[ (3\sqrt{5})^2=45, \quad (3\sqrt{5})^4=45^2=2025, \] \[ f(3\sqrt{5})=-2025+90\times 45+1000=-2025+4050+1000=3025. \] Thus, there is a local maximum at \( x=\pm 3\sqrt{5} \) with \( f(x)=3025 \) and a local minimum at the ends as \( f(x) \to -\infty \). **Answer Selections** - Domain: A. \( (-\infty, \infty) \). - \( x \)-intercepts: A. \( x=-10, \, 10 \). - \( y \)-intercept: A. \( y=1000 \).

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To summarize the pertinent information from the function \( f(x)=(x^2+10)(100-x^2) \): 1. The domain of \( f \) is \( (-\infty, \infty) \) because both components \( x^2 + 10 \) and \( 100 - x^2 \) are defined for all real numbers. Thus, all values of \( x \) can be plugged into the function without restrictions. 2. The \( x \)-intercepts occur where \( f(x) = 0 \). Setting \( (x^{2}+10)(100-x^{2}) = 0 \) reveals that \( 100 - x^2 = 0 \) gives us the intercepts \( x = -10 \) and \( x = 10 \), since \( x^2 + 10 = 0 \) has no real solutions. 3. For the \( y \)-intercept, we find \( f(0) = (0^2 + 10)(100 - 0^2) = 10 \cdot 100 = 1000 \). Thus, the \( y \)-intercept is \( y = 1000 \). So, to fill in your selections: - A. The domain of \( f \) is \( (-\infty, \infty) \). - A. The \( x \)-intercept(s) of \( f \) is/are \( x = -10, 10 \). - A. The \( y \)-intercept of \( f \) is \( y = 1000 \).

Related Questions

\( \varphi=\arctan \left(\frac{y}{x}\right) \) Penulisan system koordinat polar adalah \( \boldsymbol{r} \angle \boldsymbol{\varphi} \) Sebaliknya, untuk mengkonversi dari system koordinat polar menuju system koordinat cartesian seperti pada persamaan berikut: \( x=r \cdot \cos (\varphi) \) \( y=r \cdot \sin (\varphi) \) Untuk operasi penjumlahan dan pengurangan harus diubah ke system koordinat cartesian. Sedangkan untuk operasi perkalian dan pembagian dapat dilakukan dengan sangat mudah. Misal \( A=4 \angle 60^{\circ} \) dan \( B=2 \angle 20^{\circ} \) Perkalian: \( A \cdot B=\left(4 \angle 60^{\circ}\right) \cdot\left(2 \angle 20^{\circ}\right) \) Dalam proses perkalian, jari-jari (r) dikalikan, sedangkan sudut \( (\varphi) \) dijumlahkan. \( A \cdot B=(4.2) \angle\left(60^{\circ}+20^{\circ}\right) \) A. \( B=8 \angle 80^{\circ} \) Pembagian: \[ \frac{A}{B}=\frac{4 \angle 60^{\circ}}{2 \angle 20^{\circ}} \] Dalam proses pembagian, jari-jari (r) dibagi seperti biasa, sedangkan sudut \( (\varphi) \) pembilangdikurangi sudut penyebut. \[ \begin{array}{l} \frac{A}{B}=\frac{4}{2} \angle\left(60^{\circ}-20^{\circ}\right) \\ \frac{A}{B}=2 \angle 40^{\circ} \end{array} \] Tugas 1. (harus diseertai dengan cara) 1. Tentukan hasil dari \( \sqrt{-13.69} \) Diketahui \( A=1.5+0.5 i \) dan \( B=1+2.5 i \), maka tentukan: 2. \( A+B \) 3. \( A-B \) 4. \( A * B \) 5. \( \frac{A}{B} \) 6. \( \frac{A^{2}-A B}{B} \) 7. Bentuk polar \( A \) 8. Bentuk polar \( B \) 9. \( A * B \) dengan cara polar 10. \( \frac{A}{B} \) dengan cara polar 11. Bentuk cartesian dari jawaban no. 9 dan bandinglan hasilnya dengan jawaban no. 4 12. Bentuk cartesian dari jawaban no. 10 dan bandingkan hasilnya dengan jawaban no.5. Materi selanjutnya -> Euler dan Teorema de Moivre.

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