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2h.AP5-3.15 Check My Wor Please make sure to properly format your answers. All dollar figures in the answers need to include the dollar sign and any amount on should include the comma ( \( \$ 2,354.67 \) ). All percentage values in the answers need to include a percentage sign (\%). For all items witho fic rounding instructions, round your answers to two decimal places, show both decimol places (5.06). Whe receives a piecework rate of 10 cents per unit from the Wiggy Factory. Her production for last week was affected by a machiner akdown on Tuesday. Her production results were: Monday, 375 units; Tuesday, 22 units; Wednesday, 410 units; Thursday, 390 t5; and Friday, 390 units. What is the mean number of units produced per day? What is the median number of units produced? What is the mode number of units produced?

Ask by Harmon Nguyen. in the United States
Mar 06,2025

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Answer

- **Mean:** \$317.40 units - **Median:** \$390 units - **Mode:** \$390 units

Solution

Below is the step‐by‐step solution in markdown with LaTeX formatting. --- ### Production Data Whe’s production for the week was: - Monday: \(375\) units - Tuesday: \(22\) units - Wednesday: \(410\) units - Thursday: \(390\) units - Friday: \(390\) units --- ### 1. Mean Number of Units Produced per Day To find the mean, we sum the total units produced and then divide by the number of days. \[ \text{Mean} = \frac{375 + 22 + 410 + 390 + 390}{5} \] **Step 1:** Calculate the total units produced: \[ 375 + 22 = 397 \] \[ 397 + 410 = 807 \] \[ 807 + 390 = 1,197 \] \[ 1,197 + 390 = 1,587 \] **Step 2:** Divide the total by \(5\): \[ \text{Mean} = \frac{1,587}{5} = 317.40 \text{ units} \] --- ### 2. Median Number of Units Produced The median is the middle number when the data is arranged in increasing order. **Step 1:** Arrange the production values in ascending order: \[ 22,\quad 375,\quad 390,\quad 390,\quad 410 \] **Step 2:** The middle (third) value is the median: \[ \text{Median} = 390 \text{ units} \] --- ### 3. Mode Number of Units Produced The mode is the value that appears most frequently. **Step 1:** Inspect the list: - \(22\) appears once. - \(375\) appears once. - \(390\) appears twice. - \(410\) appears once. **Step 2:** The number that appears most frequently is: \[ \text{Mode} = 390 \text{ units} \] --- ### Final Answers - **Mean:** \(317.40\) units - **Median:** \(390\) units - **Mode:** \(390\) units

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To find the mean number of units produced per day, you add the total units produced: \( 375 + 22 + 410 + 390 + 390 = 1,587 \). Then divide by the number of days (5), giving you a mean of \( \frac{\$1,587}{5} = \$317.40 \). For the median, you need to sort the production numbers: 22, 375, 390, 390, 410. Since there are 5 numbers, the median (the middle value) is the third number, which is 390 units. The mode is the number that appears most frequently in the list, which is 390 units, as it appears twice.

Related Questions

Question 12(Mulliple Choice Warth 5 points) \[ (04.06 \mathrm{HC}) \] A researcher wants to test the claim that the proportion of juniors who watch television regularly is greater than the proportion of seniors who watch television regularly She finds that 56 of 70 randomly selected juniors and 47 of 85 randomly selected seniors report watching television regularly. Construct \( 95 \% \) confidence intervals for each population proportion. Which of the statemente gives the correct outcome of the research or's tert of the dalim? The \( 95 \% \) confidence interval for juniors is (706, 894), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is (721, 879), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( 706,894 ), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( \( 721, .879 \) ), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors.

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