Question

2. What is the smallest possible length of screw needed to pass through two pieces of wood, one that is \( \frac{7}{8} \) inch thick and one that is \( \frac{1}{4} \) inch thick?

Ask by Riley Curry. in the United States
Mar 11,2025

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Tutor-Verified Answer

Answer

The smallest possible length of screw needed is \( 1\frac{1}{8} \) inches or 1.125 inches.

Solution

To find the smallest possible length of screw needed to pass through two pieces of wood, we need to add the thickness of both pieces of wood. Given: - Thickness of the first piece of wood: \( \frac{7}{8} \) inch - Thickness of the second piece of wood: \( \frac{1}{4} \) inch The smallest possible length of screw needed is the sum of the thickness of both pieces of wood. Let's calculate the sum of the thickness of both pieces of wood: \[ \text{Smallest possible length of screw} = \frac{7}{8} + \frac{1}{4} \] Now, let's calculate the sum: Calculate the value by following steps: - step0: Calculate: \(\frac{7}{8}+\frac{1}{4}\) - step1: Reduce fractions to a common denominator: \(\frac{7}{8}+\frac{2}{4\times 2}\) - step2: Multiply the numbers: \(\frac{7}{8}+\frac{2}{8}\) - step3: Transform the expression: \(\frac{7+2}{8}\) - step4: Add the numbers: \(\frac{9}{8}\) The smallest possible length of screw needed to pass through two pieces of wood, one that is \( \frac{7}{8} \) inch thick and one that is \( \frac{1}{4} \) inch thick, is \( 1\frac{1}{8} \) inches or 1.125 inches.

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To determine the smallest possible length of screw needed to pass through two pieces of wood, we simply need to add the thicknesses of both pieces. The first piece is \( \frac{7}{8} \) inch thick, and the second piece is \( \frac{1}{4} \) inch thick. We can convert \( \frac{1}{4} \) inch to an equivalent fraction with a common denominator of 8 for easier addition: \( \frac{1}{4} = \frac{2}{8} \). Now we can add the two fractions: \[ \frac{7}{8} + \frac{2}{8} = \frac{9}{8} \] Therefore, the smallest possible length of screw required to pass through both pieces of wood is \( \frac{9}{8} \) inches, or 1 inch and 1/8 inch.

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