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Calc I: Find the derivative: \( \qquad 9) x^{2}+y^{2}=x y \)

Ask by Coles Henry. in the United States
Mar 11,2025

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Tutor-Verified Answer

Answer

The derivative is \( \frac{dy}{dx} = \frac{y - 2x}{2y - x} \).

Solution

Find the first order derivative with respect to \( x \) for \( x^{2}+y^{2}=x*y \). Find the first derivative by following steps: - step0: Find the derivative with respect to \(x\): \(x^{2}+y^{2}=xy\) - step1: Take the derivative: \(\frac{d}{dx}\left(x^{2}+y^{2}\right)=\frac{d}{dx}\left(xy\right)\) - step2: Calculate the derivative: \(2x+2y\frac{dy}{dx}=\frac{d}{dx}\left(xy\right)\) - step3: Calculate the derivative: \(2x+2y\frac{dy}{dx}=y+x\frac{dy}{dx}\) - step4: Move the expression to the left side: \(2y\frac{dy}{dx}-x\frac{dy}{dx}=y-2x\) - step5: Add and subtract: \(\left(2y-x\right)\frac{dy}{dx}=y-2x\) - step6: Divide both sides: \(\frac{\left(2y-x\right)\frac{dy}{dx}}{2y-x}=\frac{y-2x}{2y-x}\) - step7: Divide the numbers: \(\frac{dy}{dx}=\frac{y-2x}{2y-x}\) The derivative of the given function \(x^{2}+y^{2}=xy\) with respect to \(x\) is \(\frac{dy}{dx}=\frac{y-2x}{2y-x}\).

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Bonus Knowledge

To find the derivative of the equation \( 9) x^{2}+y^{2}=x y \) implicitly, start by differentiating both sides with respect to \( x \). This leads to \( 2x + 2y\frac{dy}{dx} = y + x\frac{dy}{dx} \). Rearranging gives you \( \frac{dy}{dx}(2y - x) = y - 2x \). Finally, solve for \( \frac{dy}{dx} \): \[ \frac{dy}{dx} = \frac{y - 2x}{2y - x} \] This gives you the slope of the curve defined by the original equation. Did you know that implicit differentiation is a powerful tool often used in calculus to find derivatives of equations that cannot easily be solved for one variable? It allows mathematicians and engineers to handle complex relationships without rearranging them, making it easier to find slopes and rates of change. Another fun aspect is the application of these derivatives in real-life scenarios, such as optimizing functions in engineering or physics. When dealing with systems like projectile motion or electrical circuits, understanding the relationships between variables can help in making predictions and solving real-world problems!

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