Question
upstudy study bank question image url

The amount of radium-226 remaining in a sample that originally contained A grams is approximately \( C(t)=A 0.999567^{\prime} \) where \( t \) is time in years. What is the half-life of radium- \( 226 ? \)

Ask by George Frank. in Canada
Mar 09,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The half-life of radium-226 is approximately 1602 years.

Solution

Sign in to Unlock Answers for Free!

A Learning Platform Trusted by Millions of Real Students and Teachers.

star-icon Unlock

Answered by UpStudy AI and reviewed by a Professional Tutor

Mind Expander

To find the half-life of radium-226, we set \( C(t) = \frac{A}{2} \). Substituting the function we have: \[ \frac{A}{2} = A \cdot 0.999567^{t} \] Dividing both sides by \( A \) (assuming \( A \neq 0 \)), we get: \[ \frac{1}{2} = 0.999567^{t} \] To solve for \( t \), we can take the logarithm of both sides: \[ \log\left(\frac{1}{2}\right) = t \cdot \log(0.999567) \] Now, rearranging gives us: \[ t = \frac{\log(0.5)}{\log(0.999567)} \] Calculating this will yield the half-life of radium-226. It turns out that this calculation will show you that the half-life of radium-226 is approximately about 1,600 years! The beauty of decay rates provides a fascinating glimpse into how powerful elements, like radium-226, play their role in the natural world. They serve as a reminder of nature’s impressive dynamics, where tiny atomic particles can persist over millennia, slowly transforming over time. Isn’t it amazing to think about the ancient light that shines just beneath the surface of our world? When dealing with half-lives, one common mistake is to confuse it with the concept of decay constant. The decay constant relates directly to the half-life, and they can sometimes be swapped in calculations, leading to confusion. Always remember: knowing how long it takes for half to decay is essential for accurately predicting the amount of substance left over time! This distinction can make all the difference in scientific calculations.

Related Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy