The 5 number summary and IQR have been calculated for you. Min: \( 0 \quad \) Q1:4 Median:9 Max:95 Leave your answers as decimals if needed. Don't round. The low end value is The high end value is Does this data set have outliers? Type Yes or No Ther

To determine if the data set has outliers, we need to compare the low end value and the high end value with the 5 number summary (Min, Q1, Median, Q3, Max) provided. Given: Min: 0 Q1: 4 Median: 9 Max: 95 The low end value is 0 and the high end value is 95. To determine if there are outliers, we need to check if any data points are more than 1.5 times the interquartile range (IQR) away from the first quartile (Q1) or the third quartile (Q3). The IQR is calculated as Q3 - Q1. Q3 = 95 (Max) Q1 = 4 IQR = Q3 - Q1 = 95 - 4 = 91 Now, we check if any data points are more than 1.5 times the IQR away from Q1 or Q3. Lower bound = Q1 - 1.5 * IQR = 4 - 1.5 * 91 = 4 - 136.5 = -132.5 Upper bound = Q3 + 1.5 * IQR = 95 + 1.5 * 91 = 95 + 136.5 = 231.5 Since the low end value (0) is less than the lower bound (-132.5) and the high end value (95) is less than the upper bound (231.5), there are no outliers in the data set. Therefore, the answer is: No