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S use sin Rule and cosine Rule, Identitiogs following without 9 to evaluate the for calculator D \( \sin 15^{\prime} \cos 15^{\circ} \)

Ask by Washington Ayala. in South Africa
Mar 10,2025

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Answer

\[ \sin 15^\circ \cos 15^\circ = \frac{1}{4} \]

Solution

We start with the product \[ \sin 15^\circ \cos 15^\circ. \] A useful identity for the product of \(\sin\) and \(\cos\) of the same angle is \[ \sin \theta \cos \theta = \frac{1}{2} \sin (2\theta). \] Taking \(\theta = 15^\circ\), we get \[ \sin 15^\circ \cos 15^\circ = \frac{1}{2} \sin (2 \times 15^\circ) = \frac{1}{2} \sin 30^\circ. \] We know that \[ \sin 30^\circ = \frac{1}{2}. \] Thus, \[ \frac{1}{2} \sin 30^\circ = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}. \]

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To evaluate \(\sin 15^{\circ} \cos 15^{\circ}\) without a calculator, you can use the double angle identity for sine. This identity states that \(\sin(2\theta) = 2 \sin(\theta) \cos(\theta)\). Therefore, \(\sin 15^{\circ} \cos 15^{\circ} = \frac{1}{2} \sin(30^{\circ}) = \frac{1}{2} \cdot \frac{1}{2} = \frac{1}{4}\). Another way to verify this is by using the angle subtraction identity. You know that \( \sin(30^{\circ}) = \frac{1}{2} \) and you can express \( \sin(15^{\circ}) \) and \( \cos(15^{\circ}) \) in terms of \( \sin(30^{\circ}) \) from the right triangle ratios and the unit circle. Connect it all together and you’ll enjoy the magic of trigonometry!

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