Solve the triangle with \( c=15.65, a=13.99 \), and \( \alpha=49^{\circ} \) \( \gamma=\square \) degrees \( \beta=\square \) \( b=\square \) Round all answees to 2 places after the decimal point. Give angles in degrees (but do not type "degrees" in the answer box). As in the text, side \( a \) is opposite from angle \( \alpha \), side \( b \) is opposite from angle \( \beta \), and side \( c \) is opposite from angle \( \gamma \). If no such triangle exists, then enter DNE in each answer box. If multiple triangles exist, then enter the values of the missing sides and angles for each triangle, separated by commas.
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The Deep Dive
To solve the triangle, we will first use the given values to find the missing angles and side length using the Law of Sines. 1. **Find angle \( \gamma \)** using the Law of Sines: \[ \frac{a}{\sin(\alpha)} = \frac{c}{\sin(\gamma)} \] Substituting the known values: \[ \frac{13.99}{\sin(49^\circ)} = \frac{15.65}{\sin(\gamma)} \] \[ \sin(\gamma) = \frac{15.65 \cdot \sin(49^\circ)}{13.99} \] Calculating gives: \[ \sin(\gamma) \approx \frac{15.65 \cdot 0.7547}{13.99} \approx 0.8485 \implies \gamma \approx \arcsin(0.8485) \approx 57.73 \] 2. **Find angle \( \beta \)**: \[ \beta = 180^\circ - \alpha - \gamma \] \[ \beta = 180^\circ - 49^\circ - 57.73^\circ \approx 73.27^\circ \] 3. **Find side \( b \)** using the Law of Sines: \[ \frac{b}{\sin(\beta)} = \frac{c}{\sin(\gamma)} \] Substituting the known values: \[ b = c \cdot \frac{\sin(\beta)}{\sin(\gamma)} \] \[ b = 15.65 \cdot \frac{\sin(73.27^\circ)}{\sin(57.73^\circ)} \] \[ b \approx 15.65 \cdot \frac{0.9563}{0.8485} \approx 17.56 \] Thus, the complete solution is: \[ \gamma \approx 57.73, \beta \approx 73.27, b \approx 17.56 \] Final Rounded Answers: \[ \gamma = 57.73, \beta = 73.27, b = 17.56 \]