Question

3. Find the size of the angle \( \theta \) where \( \theta \) is acute. \( \begin{array}{ll}\text { a. } \sin \theta=0.529 & \text { c. } \tan \theta=1.8 \\ \text { b. } \cos \theta=0.493 & \text { d. } \cos \theta=0.5\end{array} \)

Ask by Young Wilson. in the Philippines
Feb 19,2025

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Answer

The angles \( \theta \) for the given trigonometric functions are approximately: a. \( \theta \approx 0.557 \) radians b. \( \theta \approx 0.516 \) radians c. \( \theta \approx 1.064 \) radians d. \( \theta \approx 1.047 \) radians

Solution

To find the size of the angle \( \theta \) where \( \theta \) is acute, we can use the inverse trigonometric functions. Given: a. \( \sin \theta = 0.529 \) b. \( \cos \theta = 0.493 \) c. \( \tan \theta = 1.8 \) d. \( \cos \theta = 0.5 \) We can use the inverse sine, inverse cosine, and inverse tangent functions to find the angle \( \theta \) in each case. Let's calculate the angle \( \theta \) for each given trigonometric function: Calculate the value by following steps: - step0: Calculate: \(\arcsin\left(0.529\right)\) Calculate or simplify the expression \( \arcsin(0.493) \). Calculate the value by following steps: - step0: Calculate: \(\arcsin\left(0.493\right)\) Calculate or simplify the expression \( \arctan(1.8) \). Calculate the value by following steps: - step0: Calculate: \(\arctan\left(1.8\right)\) Calculate or simplify the expression \( \arccos(0.5) \). Calculate the value by following steps: - step0: Calculate: \(\arccos\left(0.5\right)\) - step1: Calculate the trigonometric value: \(\frac{\pi }{3}\) The size of the angle \( \theta \) where \( \theta \) is acute for each given trigonometric function is as follows: a. \( \theta \approx 0.557422 \) radians b. \( \theta \approx 0.515535 \) radians c. \( \theta \approx 1.063698 \) radians d. \( \theta \approx 1.047198 \) radians Therefore, the size of the angle \( \theta \) where \( \theta \) is acute for each given trigonometric function is approximately the values calculated above.

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To find the angle \( \theta \) where \( \theta \) is acute, we can use the inverse trigonometric functions for each case. For \( \sin \theta = 0.529 \), using \( \theta = \arcsin(0.529) \), we find \( \theta \approx 31.8^\circ \). For \( \cos \theta = 0.493 \), we get \( \theta = \arccos(0.493) \approx 60.3^\circ \). The tangent case, \( \tan \theta = 1.8 \), yields \( \theta \approx 60.3^\circ \). As for \( \cos \theta = 0.5 \), the angle is \( \theta = 60^\circ \). Therefore, the angles found are approximately \( 31.8^\circ \), \( 60.3^\circ \), and \( 60^\circ \). The smallest acute angle from all the calculations is approximately \( 31.8^\circ \), corresponding to option a, where \( \sin \theta = 0.529 \). Remember to ensure that the angles calculated remain in the range of acute angles (0° to 90°)!

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