Question

A square prism measuring 2 m by 2 m in base length and 5 m in height has a half-sphere attached to the top. What is the total surface area of this composite solid?

Ask by Newton Franklin. in the United States
Jan 14,2025

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The total surface area of the composite solid is \(44 + 2\pi\) square meters.

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To find the total surface area of the composite solid, we need to calculate the surface areas of the square prism and the half-sphere separately, then combine them. 1. **Surface Area of the Square Prism:** The square prism has a base that is a square with side length \( 2 \, \text{m} \) and a height of \( 5 \, \text{m} \). - Area of the base (bottom): \[ \text{Base Area} = 2 \times 2 = 4 \, \text{m}^2 \] - Area of the sides (4 rectangles): \[ \text{Lateral Area} = 4 \times (\text{base length} \times \text{height}) = 4 \times (2 \times 5) = 40 \, \text{m}^2 \] - Total surface area of the prism (excluding the top base): \[ \text{Total Prism Area} = \text{Base Area} + \text{Lateral Area} = 4 + 40 = 44 \, \text{m}^2 \] 2. **Surface Area of the Half-Sphere:** The radius of the half-sphere is half of the base length of the prism: \[ r = \frac{2}{2} = 1 \, \text{m} \] - Surface area of a full sphere: \[ \text{Sphere Area} = 4\pi r^2 = 4\pi (1)^2 = 4\pi \, \text{m}^2 \] - Since we only have a half-sphere: \[ \text{Half-Sphere Area} = 2\pi r^2 = 2\pi (1)^2 = 2\pi \, \text{m}^2 \] 3. **Total Surface Area of the Composite Solid:** Since the top base of the prism is covered by the half-sphere, we do not include it in the calculations for the total surface area: \[ \text{Total Surface Area} = \text{Total Prism Area} + \text{Half-Sphere Area} = 44 + 2\pi \] Calculating \(2\pi\) (approximately \(6.28\)): \[ \text{Total Surface Area} \approx 44 + 6.28 \approx 50.28 \, \text{m}^2 \] Thus, the total surface area of the composite solid is approximately: \[ \text{Total Surface Area} \approx 50.28 \, \text{m}^2 \]

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