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Sasha is carrying out a survey of her class to see how many people own a mobile phone or a laptop. The proportion of people who own a mobile phone is 0.6 The proportion of people who own a laptop is \( 35 \% \) From these results, Sasha thinks that some people in her class must own neither a mobile phone nor a laptop. Is Sasha correct? Write a sentence to explain your answer.

Ask by Hampton Lane. in the United Kingdom
Mar 08,2025

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Answer

Yes, Sasha is correct. Even if no one owns both a mobile phone and a laptop, at least 5% of the class owns neither.

Solution

1. Let \( p(M) = 0.6 \) be the proportion of people who own a mobile phone and \( p(L) = 0.35 \) be the proportion of people who own a laptop. 2. Using the formula for the union of two events, we have \[ p(M \cup L) = p(M) + p(L) - p(M \cap L) \] Since \( p(M \cap L) \geq 0 \), the maximum value of \( p(M \cup L) \) is \[ p(M) + p(L) = 0.6 + 0.35 = 0.95 \] 3. Even if no student owns both devices (i.e., \( p(M \cap L) = 0 \)), at most \( 95\% \) of the class owns a mobile phone or a laptop. This means at least \[ 1 - 0.95 = 0.05 \] or \( 5\% \) of the class would own neither. 4. If some students own both devices, then \( p(M \cap L) > 0 \) and \[ p(M \cup L) = 0.6 + 0.35 - p(M \cap L) < 0.95 \] which would result in an even higher percentage of students owning neither. Yes, Sasha is correct because even in the best-case scenario where there is no overlap, at least \( 5\% \) of the class would own neither a mobile phone nor a laptop, and this percentage increases if there is any overlap.

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Bonus Knowledge

To determine if Sasha is correct, we can analyze the proportions: 0.6 (or 60%) of her classmates own a mobile phone, and 35% own a laptop. If we assume there is no overlap (i.e., no one owns both), the total would be 95% of the class owning either a mobile phone or a laptop. This suggests that at least 5% might own neither, supporting Sasha's belief. However, without more information about the overlap, we cannot be certain.

Related Questions

Question 12(Mulliple Choice Warth 5 points) \[ (04.06 \mathrm{HC}) \] A researcher wants to test the claim that the proportion of juniors who watch television regularly is greater than the proportion of seniors who watch television regularly She finds that 56 of 70 randomly selected juniors and 47 of 85 randomly selected seniors report watching television regularly. Construct \( 95 \% \) confidence intervals for each population proportion. Which of the statemente gives the correct outcome of the research or's tert of the dalim? The \( 95 \% \) confidence interval for juniors is (706, 894), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is (721, 879), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( 706,894 ), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( \( 721, .879 \) ), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors.

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