Find the alitiude of a right triangle given that the two lengths of the segment that make up the base are 8 and 1.

To find the altitude of a right triangle when given the lengths of the segments that make up the base, we first need to clarify that those segments likely refer to the two legs of the triangle. In this case, we can use the lengths of 8 and 1 as the two legs (let's call them a and b). The area \(A\) of a right triangle can be calculated using the formula \(A = \frac{1}{2} \times a \times b\). We can also express the area in terms of the base and height; for example, if we consider one of the legs as the base, the altitude can be calculated from the area. Since the area can also be calculated as \(\frac{1}{2} \times \text{base} \times \text{height}\), we can rearrange this to find the height if we have a defined base. By treating the leg of length 8 as the base, the height (altitude) can be calculated using: 1. The area \(A = \frac{1}{2} \times 8 \times 1 = 4\). 2. Setting it equal to the alternate expression for area: \(A = \frac{1}{2} \times \text{base} \times \text{height}\). Assuming the base is 8, the formula \(4 = \frac{1}{2} \times 8 \times h\) leads to \(h = 1\). Thus, the altitude of the triangle is 1. Altogether, in a right triangle, knowing the dimensions of the sides allows for an easy computation of the area and, subsequently, the altitude through various relationships of triangle properties. Happy calculating!