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A random sample of 858 births in a state included 422 boys. Construct a \( 95 \% \) confidence interval estimate of the proportion of boys in all births. It is believed that among all births, If Do these sample results provide strong evidence against that belief? Construct a \( 95 \% \) confidence interval estimate of the proportion of boys in all births. \( 0.458
Ask by Norris Evans. in the United States
Mar 15,2025

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The confidence interval for the proportion of boys is \( 0.458 < p < 0.526 \). Since \( 0.513 \) is within this interval, the sample results do not provide strong evidence against the belief that the proportion of boys is \( 0.513 \).

Solución

We start with the data: a sample of \( n = 858 \) births includes \( x = 422 \) boys. The sample proportion is \[ \hat{p}=\frac{x}{n}=\frac{422}{858}\approx0.491. \] Next, we estimate the standard error (SE) of \(\hat{p}\): \[ \text{SE}=\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}=\sqrt{\frac{0.491(1-0.491)}{858}}=\sqrt{\frac{0.491 \times 0.509}{858}}. \] Calculating the product in the numerator: \[ 0.491 \times 0.509\approx0.250. \] Thus, \[ \text{SE}\approx\sqrt{\frac{0.250}{858}}\approx\sqrt{0.000291}\approx0.0171. \] For a \( 95\% \) confidence interval, the critical value (from the standard normal distribution) is approximately \( z^*=1.96 \). The margin of error (ME) is then \[ \text{ME}=z^*\times\text{SE}\approx1.96\times0.0171\approx0.0335. \] Now, the \( 95\% \) confidence interval for the proportion \( p \) is given by \[ \hat{p}\pm\text{ME} \quad \Longrightarrow \quad 0.491\pm0.0335. \] This gives us \[ \text{Lower bound} \approx 0.491 - 0.0335 = 0.4575, \] \[ \text{Upper bound} \approx 0.491 + 0.0335 = 0.5245. \] Rounded to three decimal places, the confidence interval is approximately \[ 0.458 < p < 0.525. \] In the problem statement, the interval is given as \( 0.458 < p < 0.526 \); the slight difference in the upper bound is due to rounding differences. Next, we compare this interval with the claimed value \( p = 0.513 \). Since \[ 0.458 < 0.513 < 0.525 \quad (\text{or } 0.526), \] the value \( 0.513 \) is contained within the \( 95\% \) confidence interval. Therefore, these sample results do not provide strong evidence against the belief that the proportion of boys among all births is \( 0.513 \). The correct response is: B. There is not strong evidence against \( 0.513 \) as the value of the proportion of boys in all births because \( 0.513 \) is contained within the \( 95\% \) confidence interval.

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To construct the 95% confidence interval for the proportion of boys, we first calculate the sample proportion, \( \hat{p} \), which is \( \frac{422}{858} \approx 0.492 \). Next, we find the standard error, \( SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \approx 0.017 \). The margin of error at 95% confidence for a normal distribution is roughly 1.96, so \( ME = 1.96 \times SE \). Thus, the confidence interval is \( \hat{p} \pm ME \), giving us \( 0.458 < p < 0.526 \). B. There is not strong evidence against 0.513 as the value of the proportion of boys in all births because 0.513 is contained within the \( 95\% \) confidence interval. Since our interval ranges from 0.458 to 0.526, it hugs that hypothesis quite comfortably, suggesting that while there might be slight fluctuations, it doesn't radically alter our initial belief.

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